Question

Ребят прошу помогите пожалуйста.решить дроби цепочкой.​

Answer 1

Ответ:

а) ((3+2)+(1/4+1/6))×1/2×3/5+47/4×1/47+63/2×12/7=(5+5/12)×1/2×3/5+1/4+9×6=5 5/12×1/2×3/5+1/4+54=65/12×1/2×3/5+1/4+54=13/4×1/2+1/4+54=13/8+1/4+54=447/8

б) 63/2×5/7+((3+2)+(1/4+1/3))×1/2×1/6=9/2×5+(5+7/12)×1/2×1/6=45/2+5 7/12×1/2×1/6= 45/2+67/12×1/2×1/6=45/2+67/144=3307/144

в) 41/10×5/6+(41/10-49/15)×1/5=41/2×1/6+5/6×1/5=41/12+1/6=43/12