Question

Помогите, даю много баллов
Номер 2 и желательно 3 (вариант 1)

Answer 1

2.а)

${(3 \frac{3}{8} )}^{ - \frac{2}{3} } = {( \frac{27}{8}) }^{ - \frac{2}{3} } = {( \frac{8}{27}) }^{ \frac{2}{3} } = \\ = { \sqrt[3]{ \frac{8}{27} } }^{2} = {( \frac{2}{3} )}^{2} = \frac{4}{9}$

2.б)

${( - 3)}^{ - 2} \times {81}^{ \frac{1}{4} } = { ( - \frac{1}{3} ) }^{2} \times { \sqrt[4]{81} }^{} = \\ = \frac{1}{9} \times 3 = \frac{1}{3}$

2.в)

$2 \times {4}^{0.4} \times \sqrt[5]{2} = 2 \times {4}^{ \frac{2}{5} } \times \sqrt[5]{2} = 2 \times { \sqrt[5]{4} }^{2} \times \sqrt[5]{2} = 2 \times \sqrt[5]{16} \times \sqrt[5]{2} = 2 \times \sqrt[5]{32} = 2 \times 2 = 4$

2.г)

${( \frac{1}{64}) }^{ - \frac{1}{6} } \times {( \frac{1}{64}) }^{ - \frac{2}{3} } = {( \frac{1}{64}) }^{ - \frac{1}{6} + ( - \frac{2}{3} )} = {( \frac{1}{64}) }^{ - \frac{5}{6} } = {64}^{ \frac{5}{6} } = { \sqrt[6]{64} }^{5} = { \sqrt[6]{ {2}^{6} } }^{5} = {2}^{5} = 32$

3.а)

${a}^{ \frac{1}{6} } \times {a}^{ \frac{4}{3} } \times {a}^{ \frac{1}{2} } = {a}^{ \frac{1}{6} + \frac{4}{3} + \frac{1}{2} } = {a}^{ \frac{1}{6} + \frac{8}{6} + \frac{3}{6} } = {a}^{ \frac{12}{6} } = {a}^{2}$

3.б)

${b}^{ - \frac{1}{3} } \div {b}^{2} = {b}^{ - \frac{1}{3} - 2 } = {b}^{ - 2 \frac{1}{3} }$

3.в)