Question

СРОЧНО ПОМОГИТЕ ЖПЖПЖПЖП ДАМ 30 БАЛЛОВ ​

Answer 1

Ответ:

Объяснение:

1) $a^{2}-9=(a-3)(a+3)$

2) $4-y^{2}=(2-y)(2+y)$

3) $\frac{4}{9}-x^{2}=(\frac{2}{9}-x)(\frac{2}{9}+x)$

4) $9x^{2}-4=(3x+2)(3x-2)$

5) $9a^{2}-16m^{2}=(3a+4m)(3a-4m)$

6) $a^{2}-0.01=(a-0.1)(a+0.1)$

7) $b^{2}+1=b^{2}+2b-2b+1=(b+1)^{2} -2b$

8) $9-b^{4}=(3+b^{2})(3-b^{2})$

9) $48m^{2}-n^{2}=(\sqrt{48}m-n)(\sqrt{48}m+n)$

10) $36m^{6}-49k^{4}n^{2}=(6m^{3}-7k^{2}n)(6m^{3}+7k^{2}n)$

11) $x^{6}-1.44=(x^{3}-1.2)(x^{3}+1.2)$

12) $\frac{1}{4}m^{2}-n^{4}=(\frac{1}{2}m-n^{2})(\frac{1}{2}m+n^{2})$

13) $\frac{16}{25}p^{4}-\frac{49}{100}q^{4}=(\frac{4}{5}p^{2}-\frac{7}{10}q^{2})(\frac{4}{5}p^{2}+\frac{7}{10}q^{2})$

14) $y^{12}-16=(y^{6}+4)(y^{6}-4)$

15) $4x^{2}y^{4}-9=(2xy^{2}-3)(2xy^{2}+3)$