Question

пжжж.....!!!!!!!!!!!!!

Answer 1

Ответ:

a) 1,5

б) -7

Объяснение:

$3sin\frac{\pi}{6}+2cos\frac{\pi}{6}-tg\frac{\pi}{3}=3*\frac{1}{2}+2*\frac{\sqrt{3}}{2}-\sqrt{3}=1,5+\sqrt{3}-\sqrt{3}=1,5\\\\\\5sin\frac{\pi}{4}+3tg\frac{\pi}{4}-5cos\frac{\pi}{4}-10ctg\frac{\pi}{4}=5*\frac{\sqrt{2}}{2}+3*1-5*\frac{\sqrt{2}}{2} -10*1=3-10=-7$