Предмет: Алгебра, автор: artemshulgaartem

1) (х-4)²-5х=
2)100+(а-5²=
3) (3х-7у)2-(3х+7у²)=
4) х(2х-9)²-х(15+х²)=

Ответы

Автор ответа: sergeydoow
1

Ответ:

1. (х-4)²-5х=

Розв'язання:

(х-4)²=5х

(х-4)²-5х+5х=5х

(х-4)²=0

х-4=0

х=4

100+(а-5²)=

Розв'язання:

100+(а-5²+5²)=

100+а-5²+5²=

100+а=5²

100+а=25

а=25-100

а=-75

(3х-7у)2-(3х+7у²)=

Розв'язання:

(3х-7у)2-(3х+7у)²+7у²=

(3х-7у)²=7у²

3х-7у=±√7у²

3х=7у±√7у²

х=7у±√7у²/3

х(2х-9)²-х(15+х²)=

Розв'язання:

х(2х-9)²-х(15+х²)= х*(2х-9)² - х*(15+х²)

х*(2х-9)² - х*(15+х²)= х*(4х²-36х+81) - х*(15+х²)

х(4х²-36х+81) - х*(15+х²)

х*(4х²-36х+81 - 15 - х²)

х*(4х²-36х+66- х²)

х=3

Объяснение:

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