Question

Пожалуйста срочно!! Задание на фото..

Answer 1

$\left \{ {{2x-\frac{x+1}{2}\geq \frac{x-1}{3}} \atop {(x+5)(x-5)+37\leq (x-6)^2 }} \right. < = > \left \{ {{\frac{3x-1}{2}\geq \frac{x-1}{3}} \atop {(x^2-25+37\leq x^2-12x+36 }} \right. < = > \\\left \{ {{9x-3\geq 2x-2} \atop {12x\leq 24 }} \right. < = > \left \{ {{x\geq \frac{1}{7}} \atop {x\leq 2 }} \right.$

Ответ: $\frac{1}{7} \leq x \leq 2$ или [$\frac{1}{7}$;2]