Question

Подайте у вигляді дробу:
1) (ax - 2a)/(3x + 9) / ((4 - x ^ 2)/(x ^ 2 + 6x + 9))
2) (ax - 3a)/(2x + 4) / ((9 - x ^ 2)/(x ^ 2 + 4x + 4))​

Answer 1

Ответ:

1)

(ax - 2a)/(3x + 9) / ((4 - x^2)/(x^2 + 6x + 9)) =

= (ax - 2a)/(3x + 9) / ( (x^2 + 6x + 9) / (x^2 + 6x + 9) ) =

= (ax - 2a)/(3x + 9) * (x^2 + 6x + 9) / (x^2 + 6x + 9) =

= (ax - 2a) * (x^2 + 6x + 9) / (3x + 9) / (x^2 + 6x + 9) =

= (ax - 2a) / (3x + 9)

2)

(ax - 3a)/(2x + 4) / ((9 - x^2)/(x^2 + 4x + 4)) =

= (ax - 3a)/(2x + 4) / ( (x^2 + 4x + 4) / (x^2 + 4x + 4) ) =

= (ax - 3a)/(2x + 4) * (x^2 + 4x + 4) / (x^2 + 4x + 4) =

= (ax - 3a) * (x^2 + 4x + 4) / (2x + 4) / (x^2 + 4x + 4) =

= (ax - 3a) / (2x + 4)

Объяснение: