Предмет: Математика, автор: amirahmadov15

Периметр трапеции равен 48см, а боковые стороны 13см и 9см. Найдите среднею линию этой трапеции.
Помогите пожалуйста

Ответы

Автор ответа: ildar502020
0

Ответ:    13 см.

Пошаговое объяснение:

АВСD  - трапеция.  P(ABCD) = 48 см. c=АВ=13 см;  d=CD =9 см.

MN=?  средняя линия трапеции.

----------------

MN=(a+b)/2 = (ВС+AD)/2;

P(ABCD) = a+b+c+d=48;

a+b=48-(c+d) = 48-(13+9) =48-22=26;

MN=26/2=13 см.

Автор ответа: zhumabekzhan567
0
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