Предмет: Химия, автор: rasukstas2

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Автор ответа: yrazgalievadiljan

Ответ:

13,072 г

Объяснение:

Все очень просто!

Fe + CuSO4 = FeSO4 + Cu 1 моль 1 моль m(CuSO4) = 16 г n(CuSO4) = 16/(64+32+16*4)=0,1 моль m(Fe) = 4,8 г n(Fe) = 4,8/56=0,086 моль - недостаток m(FeSO4) = 0,086*(56+32+16*4)=13,072 г.

Не благодари!

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