Question

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$(0.3m {}^{2} n {}^{3} ) { - }^{2} \times (3m {}^{4} n {}^{5} ) { - }^{1}$
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Answer 1

Ответ: $\frac{100}\frac{27m^8n^1^1}$

Объяснение:$(0,3^-^2m^-^2n^-^3)^-^2*(3m^4n^5)^-^1= 0,3^-^2*m^-^4n^-^6*3^-^1m^-^4n^-^5= (\frac{3}{10} )^-^2*m^-^4n^-^6*3^-^1m^-^4n^-^5= (\frac{10}{3} )^2*m^-^ n^-^6*3^-^1m^-^4n^-^5=\frac{100}{9}m^-^4n^-^6*3^-^1m^-^4n^-^5=\frac{100}{3^2}m^-^4n^-^6*3^-^1m^-^4n^-^5=\frac{100}{3^3}m^-^4n^-^6m^-^4n^-^5=\frac{100}{27}m^-^4n^-^6m^-^4n^-^5= \frac{100}{27} m^-^8n^-^1^1= \frac{100}{27}*\frac{1}{m^8}*n^-^1^1=\frac{100}{27}*\frac{1}{m^8}*\frac{1}{n^-^1^1}= \frac{100}{27m^8n^-^1^1}$