Предмет: Биология, автор: melonaaa

УМОЛЯЮ! СРОЧНО!
В процессе фотосинтеза за один световой день растение поглощает 33 г углекислого газа. Какую массу глюкозы и объем кислорода может образовать это растение за 10 дней?

Ответы

Автор ответа: nikolaygr

Відповідь:

m(CO2)=33*10=330г

M(C6H12O6)=180г/моль

6СО2+6Н2О=С6Н12О6+6О2

m(CO2)=44г/моль

n(CO2)=330/44=7,5моль

n(CO2):n(C6H12O6):n(O2)= 6:1:6

n(C6H12O6)=7,5/6=1,25моль

m(C6H12O6)=180*1,25=225г

n(O2)=7,5моль

V(O2)=22,4*7,5=168л

Пояснення:

melonaaa: большое спасибо, у меня в профиле есть еще задания по биологии, ответьте и на них, если не сложно!

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