Question

помогите алгебра - 11.2​

Answer 1

Ответ:

1) sin 420° = sin (420-360)° = sin 60° = √3/2

2) tg (-315°) = tg (-315 + 360)° = tg 45° = 1

3) sin 1110° = sin (1110 - 360*3)° = sin 30° = 1/2

4) cos 7п/3 = cos (7п/3 - 2п) = cos п/3 = 1/2