Question

632. Вычислите:
1)
3
-
4
+
5
6
-
3
5
8
7
-
1
4;
19
8
9 по g
1-
4
9
2/33-15) (;-1)+(2}+13)(32) 56
:
34 14

Answer 1

Відповідь:

$1)(\frac{3}{4}+\frac{5}{6}):(1\frac{1}{2}-\frac{3}{5})*1\frac{8}{19}-(1-\frac{7}{8})*4=\frac{19}{12}:(\frac{3}{2}-\frac{3}{5})*\frac{27}{19}-\frac{1}{8}*4=\frac{1}{12}:\frac{9}{10}*27-\frac{1}{2}=\frac{1}{12}*\frac{10}{9}*27-\frac{1}{2}=\frac{1}{6}*5*3-\frac{1}{2}=\frac{1}{2}*5-\frac{1}{2}=\frac{5}{2}-\frac{1}{2}=2$

$2)(3\frac{2}{3}-1\frac{7}{9}):(\frac{1}{2}-\frac{1}{4})+(2\frac{1}{2}+1\frac{3}{4})*(\frac{3}{34}+\frac{2}{14}):\frac{9}{56}=(\frac{11}{3}-\frac{16}{9}):\frac{1}{4}+((2+1)+(\frac{1}{2}+\frac{3}{4}))*\frac{55}{238}*\frac{56}{9}=\frac{17}{9}*4+(3+\frac{5}{4})*\frac{55}{238}*\frac{56}{9}=\frac{68}{9}+(3+1\frac{1}{4})*\frac{55}{238}*\frac{56}{9}=\frac{68}{9}+(3+1+\frac{1}{4})*\frac{55}{238}*\frac{56}{9}=\frac{68}{9}+(4+\frac{1}{4})*\frac{55}{238}*\frac{56}{9}=$

$=\frac{68}{9}+4\frac{1}{4}*\frac{55}{238}*\frac{56}{9}=\frac{68}{9}+\frac{17}{4}*\frac{55}{238}*\frac{56}{9}=\frac{68}{9}+\frac{55}{14}*\frac{14}{9}=\frac{68}{9}+55*\frac{1}{9}=\frac{68}{9}+\frac{55}{9}=\frac{41}{3}=13\frac{2}{3}$