Question

x^2-12x=0 Розв'язати рівняння

Answer 1

Ответ:

${x}^{2} - 12x = 0$

${1x}^{2} - 12x = 0$

${1x}^{2} + ( - 12x) = 0$

${1x}^{2} + ( - 12x) + 0 = 0$

$a = 1.b = - 12.c = 0$

$x = \frac{ - ( - 12)± \sqrt{ {( - 12)}^{2} - 4 \times 1 \times 0} }{2 \times 1}$

$x = \frac{12± \sqrt{ {( - 12)}^{2} - 0} }{2}$

$x = \frac{12± \sqrt{ {( - 12)}^{2} } }{2}$

$x = \frac{12± \sqrt{ {12}^{2} } }{2}$

$x = \frac{12± \sqrt[2]{ {12}^{2} } }{2}$

$x = \frac{12±12}{2}$

$x = \frac{12 + 12}{2} \\ x = \frac{12 - 12}{2}$

$x = \frac{24}{2} \\ x = \frac{0}{2}$

$x = 12 \\ x = 0$

${x}_{1}=0, {x}_{2}=12$