Question

СРОЧНО!!!!!!!!! ДАМ 100 БАЛОВ

6. Розв'яжіть рвняння 1) 12x - 4x2 = 0, 2)(3x +/4)(2x - 3) - 5 = (2x + 5)(3x - 7).​

Answer 1

$\displaystyle\bf\\1)\\\\12x-4x^{2} =0 \ |:(-4)\\\\x^{2} -3x=0\\\\x\cdot(x-3)=0\\\\\\\left[\begin{array}{ccc}x=0\\x-3=0\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1} =0\\x_{2} =3\end{array}\right\\\\\\Otvet \ : \ 0 \ ; \ 3\\\\\\2)\\\\(3x+4)(2x-3)-5=(2x+5)(3x-7)\\\\6x^{2}-9x+8x-12-5=6x^{2} -14x+15x-35\\\\6x^{2} -x-17=6x^{2} +x-35\\\\6x^{2} -x-6x^{2} -x=-35+17\\\\-2x=-18\\\\x=-18:(-2)\\\\x=9\\\\Otvet \ : \ 9$