Question

B) (6c-8)(5-2c) - 3c(c-1); перетворіть у многочлени ​

Answer 1

$(6c - 8)(5 - 2c) - 3c(c - 1) = 6c \times 5 - 6c \times 2c - 8 \times 5 + 8 \times 2c - 3c \times c + 3c = 30c - 12 {c}^{2} - 40 + 16c - 3 {c}^{2} + 3c = 49c - 15 {c}^{2} - 40$