Question

16х²-40ху+25у² якщо х=5, у=4​

Answer 1

Ответ:

$16 {x}^{2} - 40xy + 25 {y}^{2} = (4x - 5y {)}^{2} = \\ = (4 \times 5 - 5 \times 4 {)}^{2} = (20 - 20 {)}^{2} = {0}^{2} = 0$