Question

найдите производные функций 1) у=(3-4х) в пятой

2) у=под корнем 12-5х

Answer 1

1) y=(3-4x)^5

     y'=5*(3-4x)^4*(-4)

y'=-20*(3-4x)^4

2)

y=sqrt(12-5x)

y=(12-5x)^(1/2)

y'=1/(2*sqrt(12-5x))*(-5)

y'=-5/(2*sqrt(12-5x))

Answer 2

1) $y = (3-4x)^5$

$y' = 5(3-4x)^4(-4) = -20(3-4x)^4$

2) $y=sqrt{12-5x}$ 

$y' = -frac{1}{2sqrt{12-5x}}(-5) = frac{5}{2sqrt{12-5x}}$