Question

3) 25x² +16=0; пж помогите​

Answer 1

$25 {x}^{2} + 16 = 0 \\ 25 {x}^{2} = - 16 \\ \frac{25}{25} {x}^{2} = - \frac{16}{25} \\ {x}^{2} = - \frac{16}{25} \\ x = - \sqrt{ \frac{16}{25} } \\ x = - \sqrt{ - \frac{16}{25} } \\ x = \frac{4}{5} \: \: \: x = - \frac{4}{5}$