Question

помогите! срочно! задание на фото

Answer 1

Ответ:

х≠0,х≠5

$\frac{x {}^{2} - 9x + 50}{ {x}^{2} - 5x } - \frac{x + 1}{x - 5} - \frac{x - 5}{x} = 0$

$\frac{ {x}^{2} - 9x + 50 }{x \times (x - 5)} - \frac{x + 1}{x - 5} - \frac{x - 5}{x} = 0$

$\frac{ {x}^{2} - 9x + 50 - x \times (x + 1) - ( {x - 5)}^{2} }{x \times (x - 5)} = 0$

$\frac{ {x}^{2} - 9x + 50 - {x}^{2} - x - (x - 5 {)}^{2} }{x \times (x - 5 {)}^{2} } = 0$

$\frac{ - 9x + 50 - x - (x - 5 {)}^{2}}{x \times (x - 5)} = 0$

$\frac{ - 10x + 50 - (x - 5 {)}^{2} }{x \times (x - 5)} = 0$

$\frac{ - 10(x - 5) - (x - 5 {)}^{2} }{x \times (x - 5)} = 0$

$\frac{(x - 5) \times ( - 10 - (x - 5))}{x \times (x - 5)}$

$\frac{(x - 5) \times ( - 10 - x + 5)}{x \times (x - 5)} = 0$

сокращаешь (х-5)

$\frac{ - 10 - x + 5}{x} = 0$

$\frac{ - 5 - x}{x} = 0$

-5-х=0

-х=5

х= -5