Question

sin (3x + п/3) < -√2/2 Help meeeeeee pleas !!​

Answer 1

Ответ:

sin (3x + π/3) < -√2/2

Замена (3x + π/3) = a

-π - arcsin(-√2/2) + 2πk < a < arcsin(-√2/2) + 2πk , k ,€ Z

-π + π/4 + 2πk < a < -π/4 + 2πk , k € Z

- 3π/4 + 2πk < a < -π/4 + 2πk , k € Z

- 3π/4 + 2πk < 3x + π/3 < -π/4 + 2πk , k € Z

- 3π/4 - π/3 + 2πk < 3x < -π/4 - π/3 + 2πk , k € Z

- 9π/12 - 4π/12 + 2πk < 3x < -3π/12 - 4π/12 + 2πk , k € Z

- 13π/12 + 2πk < 3x < -7π/12 + 2πk , k € Z

-13π/36 + 2πk/3 < x < -7π/36 + 2πk/3 , k € Z