Предмет: Геометрия, автор: gzb9x52qcn

Знайти периметр чотирикутника АВСD, якщо сторона ВС= 7см і на 3 см коротша за сторону АD. Відповідь: см.

Ответы

Автор ответа: Rashidxon

0

Объяснение:

P=2*(BC+AD)

BC=7

AD=BC+3=7+3=10

P=2*(7+10)=2*17=34

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