Question

срочно нужен ответ!!

Answer 1

$\displaystyle\bf\\1) \ \ \frac{x+3}{x-3} +\frac{x-3}{x+3} =\frac{(x+3)\cdot(x+3)+(x-3)\cdot(x-3)}{(x-3)\cdot(x+3)} =\\\\\\=\frac{x^{2} +6x+9+x^{2} -6x+9}{x^{2} -9}=\frac{2x^{2} +18}{x^{2} -9} =\frac{2\cdot(x^{2} +9)}{x^{2} -9} \\\\\\2) \ \ \frac{2\cdot(x^{2} +9)}{x^{2} -9} :\frac{x^{2}+9 }{x^{2} -9} = \frac{2\cdot(x^{2} +9)}{x^{2} -9} \cdot\frac{x^{2}-9 }{x^{2} +9} =2\\\\\\Otvet \ : \ 2$