Question

пж поможіть умоляю поможіть умоляю поможіть ​

Answer 1

$\displaystyle\bf\\2)\\\\1) \ \ 36^{2} +2\cdot 36\cdot 14+14^{2} =(36+14)^{2} =50^{2} =2500\\\\2) \ \ 117^{2} -2\cdot 117\cdot 17+17^{2} =(117-17)^{2} =100^{2} =10000\\\\\\3)\\\\1) \ \ x^{2} +16x+64=0\\\\x^{2} +2\cdot x\cdot 8+8^{2} =0\\\\(x+8)^{2} =0\\\\x+8=0\\\\\boxed{x=-8}\\\\2) \ \ 4x^{2} +9=-12x\\\\4x^{2} +12x+9=0\\\\(2x)^{2} +2\cdot 2x\cdot 3+3^{2} =0\\\\(2x+3)^{2} =0\\\\2x+3=0\\\\2x=-3\\\\\boxed{x=-1,5}$