Предмет: Химия, автор: Lox123roz

Какая масса целлюлозы потребуется для получения 356,4 кг тринитроцеллюлозы?

Ответы

Автор ответа: kolesnikovaviktoria7

Ответ:

Ответ: 194.4 кг

Объяснение:

Дано

m(C6H7O2(ONO2)3)=356.4 кг = 356400 г -------------------------------------------------------

m(C6H10O5)-?

Решение

Xг 356400 г

C6H10O5+3HNO3-->C6H7O2(ONO2)3+3H2O

162 г/моль 297 г/моль

M(C6H10O5)=162 г/моль

M(C6H7O2(ONO2)3)=297 г/моль х = 356400*162/297 = 194400 г = 194.4 кг

Ответ: 194.4 кг

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