Question

2sin(x-п)=корен2 тендеуди шешиниз

Answer 1

Answer:

2sin(x-π) = √2

Simplify the expression

2(-sin(x)) = √2

-2sin(x) = √2

Divide both sides of the equation by -2:

sin(x) = -√2/2

Using the unite circle, finde the angle for which the sine equals -√2/2

x = 5π/4;

x = 7π/4;

Since the sine function is periodic, add the period of 2kπ, k є Z, to find the solutions:

x = 5π/4 + 2kπ, k є Z;

x = 7π/4 + 2kπ, k є Z;