Question

bx + by - 3(x+y) розкласти на множники ​

Answer 1

Ответ:

(ax+bx)-(ay+by)=x(a+b)-y(a+b)=(a+b)(x-y)

(ax-bx)+(ay-by)=x(a-b)+y(a-b)=(a-b)(x+y)

-(ax-bx)+(ay-by)=-x(a-b)+y(a-b)=(a-b)(-x+y)

(ax-bx)-(ay-by)=x(a-b)-y(a-b)=(a-b)(x-y)

Answer 2

$bx + by - 3(x + y) = b(x + y) - 3(x + y) = (x + y)(b - 3)$