Question

Самостоятельная
работис
1 5 y=x+1)
х+у=9
2)). y=x+3
{ x + y = = = 7
3) y=x=3
ј
(x+y=9
1), 2х+у=12
24-2=
2=3x
7
Пжшка помогите

Answer 1

Відповідь:5х/(х+1)-(х-4)/(х+1) = (5x-x+4)/(x+1) = 4(x+1)/(x+1) = 4

(2-х-у)/(4-у² )+х/(4-у² ) = (2-x-y+x) / (2-y)(2+y) = 1/(2+y)

(3-2х)/(х²-25)-(8-х)/(х²-25) = (3-2x-8+x) / (x-5)(x+5) = 1/(5-x)

(у²-8у)/(у-3) - (9+2у)/(3-у) = (y²-8y + 2y +9) / (y-3) = (y-3)²/ (y-3) = y-3

(29+х²)/(6-х)² -2(5х-1)/(х-6)² +(5-2х)/(6-х)² = (29 + x²- 10x +2 +5 - 2x)/ (6-x)² =

Пояснення: