Question

Додати многочлени: ( 12у² + 4y ) +( - 3у² - бу + 5 )​

Answer 1

( 12у² + 4y ) +( - 3у² - бу + 5 )​=

=12y²+4y-3y²-6y+5=9y²-2y+



Answer 2

$\displaystyle\bf\\\Big(12y^{2} +4y\Big)+\Big(-3y^{2} -6y+5\Big)=12y^{2} +4y-3y^{2} -6y+5=\\\\\\=\Big(\underbrace{12y^{2} -3y^{2} }_{9y^{2}} \Big)+\Big(\underbrace{4y-6y}_{-2y}\Big)+5=9y^{2} -2y+5$