Question

ПОМАГИТЕ ПОЖАЛУЙСТА ​

Answer 1

Ответ:

Объяснение:

$(2^{\frac{5}{3}} *3^{-\frac{1}{3}} -3^{\frac{5}{3}}*2^{-\frac{1}{3}}})\sqrt[3]{6}=(2^{\frac{6}{3}-\frac{1}{3} } *3^{-\frac{1}{3}} -3^{\frac{6}{3}-\frac{1}{3} }*2^{-\frac{1}{3}}})\sqrt[3]{6}=$

$=(\frac{2^{2} }{2^{\frac{1}{3}}*3^{\frac{1}{3}}}-\frac{3^{2} }{2^{\frac{1}{3}}*3^{\frac{1}{3}}})*6^{\frac{1}{3}}=(\frac{2^{2} }{(2*3)^{\frac{1}{3}}}-\frac{3^{2} }{(2*3)^{\frac{1}{3}}})*6^{\frac{1}{3}}=(\frac{2^{2} }{6^{\frac{1}{3}}}-\frac{3^{2} }{6^{\frac{1}{3}}})*6^{\frac{1}{3}}=\frac{2^{2}*6^{\frac{1}{3}}}{6^{\frac{1}{3}}}--\frac{3^{2}*6^{\frac{1}{3}}}{6^{\frac{1}{3}}}=2^{2}-3^{2}=4-9=-5$