Question

Допоможіть, будь ласка, пжпжпжпжпжпжпж

Answer 1

1. $7^{n}$ - 49 = $7^{n}$ + $7^{2}$ = $7^{n + 2}$
Ответ: Б) $7^{n + 2}$

2. $5^{n}$ : 25 = $5^{n}$ : $5^{2}$ = $5^{n - 2}$
Ответ: Б)  $5^{n - 2}$

3. 1) $m^{4}$$n^{5}$$m^{3}$$n^{2}$ = $m^{4 + 3}$$n^{5 + 2}$ = $m^{7}$$n^{7}$
2) $x^{10}$ : $x^{4}$ = $x^{10 - 4}$ = $x^{6}$
3) $a^{5}$$a^{7}$ : $a^{11}$ = $a^{5 + 7 - 11}$ = $a^{1}$ = $a$
4) $(a^{9})^{7}$ = $a^{9 * 7}$ = $a^{63}$
5) $(-y)$$(-y)^{2}$ = $-y$ * $y^2$ = $-y^3$

6) $\frac{(b^{6}c^{7})^{3}}{b^{16}c^{16}}$ = $\frac{b^{6 * 3}c^{7 * 3}}{b^{16}c^{16}}$ = $\frac{b^{18}c^{21}}{b^{16}c^{16}}$ = $b^{18 - 16}c^{21 - 16}$ = $b^{2}c^{5}$
7) $(3ab^{3})^{5}$ = $3^{5}a^{5}(b^{3})^{5}$ = $125a^{5}b^{15}$

8) $(\frac{x^{6}x^{3}}{x^{2}} )^{4}$ = $(x^{6 + 3 - 2})^{4}$ = $(x^{7})^{4}$ = $x^{28}$

4. 1) x * $b^3$ = $b^{18}$
x = $b^{18} : b^{3}$ = $b^{18 - 3}$ = $b^{15}$

2) x : $b^3$ = $b^{18}$
x = $b^{18} * b^{3} = b^{18 + 3} = b^{15}$
3) $b^{12} : x = b^{3}$
$x = b^{12} : b^{3} = b^{12 - 3} = b^{9}$
4) $b^{16} = (x)^{2}$

$b^{8 * 2} = (x)^{2}$

$(b^{8})^{2} = (x)^{2}$

$x = b^{8}$

5) $b^{16} = (x)^{4}$
$b^{2 * 8} = (x)^{8}$

$(b^{4})^{4} = (x)^{4}$

$x = b^{4}$

6) $b^{16} = (x)^{8}$
$(b^{2})^{8} = (x)^{8}$
$x = b^{2}$$b^{4 * 4} = (x)^{4}$