Question

допоможіть будь ласка СРОЧНО ПОЖАЛУСТА ​

Answer 1

$\displaystyle\bf\\\frac{m^{2} +2mc+c^{2} }{m^{2}+mc+c^{2} } :\frac{7m+7c}{m^{3} -c^{3} } =\frac{(m+c)^{2} }{m^{2} +mc+c^{2} } :\frac{7\cdot(m+c)}{(m-c)(m^{2} +mc+c^{2} } =\\\\\\=\frac{(m+c)^{2} }{m^{2} +mc+c^{2} } \cdot\frac{(m-c)(m^{2}+mc+c^{2} ) }{7\cdot(m+c)} =\\\\\\=\frac{(m+c)(m-c)}{7} =\frac{m^{2} -c^{2} }{7} \\\\\\\frac{m^{2} -c^{2} }{7} =\frac{m^{2} -c^{2} }{7}$

Что и требовалось доказать .

Answer 2

$\frac{ {m}^{2} + 2mc + {c}^{2} }{ {m}^{2} + mc + {c}^{2} } \div \frac{7m + 7c}{ {m}^{3} - {c}^{3} } = \frac{ {m}^{2} - {c}^{2} }{7}$

$\frac{( {m + c)}^{2} }{ {m}^{2} + mc + {c}^{2} } \div \frac{7(m + c)}{(m - c)( {m}^{2} + mc + {c}^{2} )} = \frac{(m - c)(m + c)}{7}$

$\frac{(m + c {)}^{2} }{ {m {}^{2} + mc + {c}^{2} }^{} } \times \frac{(m - c)( {m}^{2} + mc + {c}^{2}) }{7(m + c)} = \frac{(m - c)(m + c)}{7}$

$\frac{(m + c)(m - c)}{7} = \frac{(m + c)(m - c)}{7}$