Question

Розв'яжіть систему нерівностей:
[3x-4< 8
[x+6≤3x​

Answer 1

$\displaystyle\bf\\\left \{ {{3x-4 < 8} \atop {x+6\leq 3x}} \right.\\\\\\\left \{ {{3x < 8+4} \atop {x-3x\leq -6}} \right. \\\\\\\left \{ {{3x < 12} \atop {-2x\leq -6}} \right. \\\\\\\left \{ {{x < 4} \atop {x\geq 3}} \right. \\\\\\Otvet \ : \ x\in\Big[3 \ ; \ 4\Big)$