Предмет: Геометрия, автор: Аноним

два ребра прямоугольного параллелепипеда ,выходящая из одной вершины равны 3 и 4.Площадь поверхности этого параллелепипеда равна 94 см в квадрате .Найти 3 ребро выходящее из той же вершины 
с рисунком

Ответы

Автор ответа: биофизик
0
S(одной грани)= 3*4= 12. 
В параллелепипеде 2 грани по 12 то есть 12*2= 24 
Значит остальные 4 грани = 94-24=70 
2 грани от ребра 3. 
2 грани от ребра 4. 
Составим уравнение
3х+3х+4х+4х=70 
14х=70
x=70/14 

х=5 
Ответ  третье ребро= 5см
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