Предмет: Химия, автор: leonidmordusenko6

Метал 2 групи масою 6 грам без залишку прореагував з водою. При цьому виділився газ об'ємом 5,6 літрів(н.у.). Визначте метал.

СРОЧНО! ДО ЗАВТРА НУЖНО СДАТЬ! ДАЮ 50 БАЛЛОВ!!!​

Ответы

Автор ответа: zlatakorzh6
1

Ответ:

магний (Mg)

Объяснение:

Me - неизвестный металл второй группы

Me + 2HCl = MeCl2 + H2

n (Me) = n(H2) = 5,6 / 22,4 = 0,25 моль

Mr (Me) = 6 / 0,25 = 27 г/моль

Это магний (Mg)

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