Question

1) 0,4x2y·(–5xy5)2;
2)​

Answer 1

1) 0,4x2y·(–5xy5)2 = 0,4х * 2у(-25ху)*2 = -40х²у²

2) (1/2а³b⁴)⁴*16a¹⁰b² = 1|16a¹²b¹⁶*16a¹⁰b² = a¹²b¹⁶a¹⁰b² = a²²b¹⁸