Question

45 Баллов. Алгебра 8 класс

Answer 1

Ответ:

смотрим фото

Объяснение:

Answer 2

$\displaystyle\bf\\\Big(4-\sqrt{7} \Big)\Big(\sqrt{(1+\sqrt{7} )^{2} } -\sqrt{(1-\sqrt{7} )^{2} }-\sqrt{(2-\sqrt{7})^{2} } \Big)=\\\\\\=\Big(4-\sqrt{7} \Big)\Bigg(\Big|1+\sqrt{7} \Big|-\Big|1-\sqrt{7}\Big|-\Big|2-\sqrt{7}\Big|\Bigg)=\\\\\\=\Big(4-\sqrt{7} \Big)\Big(1+\sqrt{7} -\sqrt{7} +1-\sqrt{7} +2\Big)=\\\\\\=\Big(4-\sqrt{7} \Big)\cdot \Big(4-\sqrt{7} \Big)=\Big(4-\sqrt{7} \Big)^{2} =16-8\sqrt{7} +7=23-8\sqrt{7}$