Question

розв'язати4, 5 терміново

Answer 1

4. а) 3$\sqrt{2}$ = $\sqrt{3^{2} *2 }$ = $\sqrt{9*2}$=$\sqrt{18}$

б) 2а$\sqrt[3]{4a}$ = $\sqrt[3]{4a * (2a)^3} = \sqrt[3]{4a* 2^3 * a^3} = \sqrt[3]{4a* 8 * a^3} = \sqrt[3]{32a^4}$

5. $\frac{3}{\sqrt[3]{2} } = \frac{3*\sqrt[3]{2^2} }{\sqrt[3]{2} *\sqrt[3]{2^2}} = \frac{3*\sqrt[3]{2^2} }{\sqrt[3]{2^3}} = \frac{3\sqrt[3]{4} }{2}$

6. а) $\sqrt[3]{\sqrt[4]{8} } = \sqrt[3*4]{8} = \sqrt[3*4]{2^3} = \sqrt[4]{2}$

б) $\sqrt[3]{a\sqrt{a} } = \sqrt[3]{\sqrt{a* a^2} } = \sqrt[3*2]{a* a^2} =\sqrt[3*2]{a^3} = \sqrt{a}$