Question

(12у2+4у)*(-3у-6у+5)

Answer 1

Ответ:

$(12y2+ 4y) \times ( - 3y - 6y + 5) = 12y \times 2( - 3y - 6y + 5) + 4y \times ( - 3y - 6y + 5) = - 72 {y}^{2} - 144 {y}^{2} + 120y - 12{y}^{2} - 24 {y}^{2} + 20y = - 252 {y}^{2} + 140y$

Ответ: -252y²+140y