Question

вычислите (2√2-3)^2*6√8 ТОЛЬКО 3 ПРИМЕР​

Answer 1

$\displaystyle\bf\\\Big(2\sqrt{2} -3\Big)^{2} \cdot\sqrt[6]{8} =\Big[\Big(2\sqrt{2} \Big)^{2} -2\cdot 2\sqrt{2} \cdot 3+3^{2} \Big]\cdot \sqrt[6]{2^{3} } =\\\\=\Big(8-12\sqrt{2}+9 \Big)\cdot \sqrt{2} =8\sqrt{2} -12\cdot 2+9\sqrt{2} =17\sqrt{2} -24$

Answer 2

Ответ:

Объяснение:

$(2\sqrt{2}-3)^2*\sqrt[6]{8}=(8-12\sqrt{2}+9)*\sqrt[6]{2^3}=(17-12\sqrt{2})*\sqrt{2}= 17\sqrt{2} -12*2= 17\sqrt{2}-24$