Question

( \dfrac{ x }{ y ^ { 2 } } ​- \dfrac{ 1 }{ x } )÷ \left( \dfrac{ 1 }{ y } ​+ \dfrac{ 1 }{ x } ​ \right)

Answer 1

Ответ:

$( \dfrac{ x }{ y ^ { 2 } } - \dfrac{ 1 }{ x } )÷ \left( \dfrac{ 1 }{ y } + \dfrac{ 1 }{ x } \right)$

$\frac{ {x}^{2} - {y}^{2} }{x {y}^{2} } \div \frac{x + y}{xy}$

$\frac{(x - y) \times (x + y)}{x {y}^{2} } \times \frac{xy}{x + y}$

$\frac{x - y}{y}$