Question

Помогите пожалуйста, срочно надо!!!!!!

Answer 1

Ответ:

1)

$\frac{3x - 7}{8} - \frac{x - 3}{6} = 1$

$\frac{3x - 7}{8} \times ( \frac{x}{6} - \frac{1}{2}) = 1$

$\frac{3x}{8} - \frac{7}{8} + ( - \frac{x}{6} + \frac{1}{2} ) = 1$

$\frac{5x}{24} - \frac{3}{8} = 1$

$\frac{5}{24} \times x - \frac{3}{8} + \frac{3}{8} = 1 + \frac{3}{8}$

$\frac{5}{24} \times x = 1 + \frac{3}{8}$

$\frac{x \times (\frac{5}{24}) }{ \frac{5}{24} } = \frac{1 + \frac{3}{8} }{ \frac{5}{24} }$

$x = \frac{1 + \frac{3}{8} }{ \frac{5}{24} }$

$x = \frac{ \frac{11}{8} }{ \frac{5}{24} }$

$x = \frac{11}{8} \times ( \frac{24}{5} )$

$x = \frac{33}{5}$

2)

$(3x + 4)(4x - 3) - 5 = (2x + 5)(6x - 7)$

$(3x + 4)(4x - 3) - 5 - (2x + 5)(6x - 7) = (2x + 5)(6x - 7) - (2x + 5)(6x - 7)$

$(3x + 4)(4x - 3) - 5 - (2x + 5)(6x - 7) = 0$

$3x(4x - 3) + 4(4x - 3) - 5 - 1((2x + 5)(6x - 7)) = 0$

$3x(4x) + 3x( - 3) + 4(4x - 3) - 5 - 1((2x + 5)(6x - 7) = 0$

$12xx + 3x( - 3) + 4(4x - 3) - 5 - 1((2x + 5)(6x - 7)) = 0$

$12 {x}^{2} + 3x( - 3) + 4(4x - 3) - 5 - 1((2x + 5)(6x - 7)) = 0$

$12 {x}^{2} - 9x + 4(4x - 3) - 5 - 1((2x + 5)(6x - 7)) = 0$

$12 {x}^{2} - 9x + (4(4x) + 4( - 3)) - 5 - 1((2x + 5)(6x - 7)) = 0$

$12 {x}^{2} - 9x + (16x + 4( - 3)) - 5 - 1((2x + 5)(6x - 7)) = 0$

$12 {x}^{2} - 9x + (16x - 12) - 5 - 1((2x + 5)(6x - 7)) = 0$

$12 {x}^{2} - 9x + ( - 12 + 16x) - 5 - 1((2x + 5)(6x - 7)) = 0$

$12 {x}^{2} + 7x - 12 - 5 - 1((2x + 5)(6x - 7)) = 0$

$12 {x}^{2} + 7x - 17 - 1((2x + 5)(6x - 7) = 0$

$12 {x}^{2} + 7x - 17 - 1(2x(6x - 7) + 5(6x - 7)) = 0$

$12 {x}^{2} + 7x - 17 - 1(2x(6x) + 2x( - 7) + 5(6x - 7)) = 0$

$12 {x}^{2 } + 7x - 17 - 1(12xx + 2x( - 7) + 5(6x - 7)) = 0$

$12 {x}^{2} + 7x - 17 - 1(12 {x}^{2} + 2x( - 7) + 5(6x - 7)) = 0$

$12 {x}^{2} + 7x - 17 - 1(12 {x}^{2} - 14x + 5(6x - 7)) = 0$

$12 {x}^{2} + 7x - 17 - 1(12 {x}^{2} - 14x + (5(6x) + 5( - 7))) = 0$

$12 {x}^{2} + 7x - 17 - 1(12 {x}^{2} - 14x + (30x + 5( - 7))) = 0$

$12 {x}^{2} + 7x - 17 - 1(12 {x}^{2} - 14x + (30x - 35)) = 0$

$12 {x}^{2} + 7x - 17 - 1(12 {x}^{2} - 14x + ( - 35 + 30x)) = 0$

$12 {x}^{2} + 7x - 17 - 1(12 {x}^{2} + 16x - 35) = 0$

$12 {x}^{2} + 7x - 17 + (( - 1)(12 {x}^{2} ) - 1(16x) + ( - 1)( - 35)) = 0$

$12 {x}^{2} + 7x - 17 + (( - 12) {x}^{2} - 1(16x) + ( - 1)( - 35)) = 0$

$12 {x}^{2} + 7x - 17 + ( - 12 {x}^{2} - 16x + ( - 1)( - 35)) = 0$

$12 {x}^{2} + 7x - 17 + ( - 12 {x}^{2} - 16x + 35) = 0$

$- 9x + 18 = 0$

$- 9x + 18 - 18 = 0 - 18$

$- 9x = - 18$

$\frac{( - 9)x}{ - 9} = \frac{ - 18}{ - 9}$

$x = 2$