Question

ПОМОГИТЕ СРОЧНОООООО!!!!!!!!!!!!!!!!!!!!

Answer 1

Ответ:

Ответ:4

Объяснение:

Answer 2

$\displaystyle\bf\\1)\\\\\frac{m-3}{m+3}-\frac{m+3}{m-3} =\frac{(m-3)(m-3)-(m+3)(m+3)}{(m+3)(m-3)} =\\\\\\=\frac{m^{2} -6m+9-m^{2} -6m-9}{m^{2}-9 } =\frac{-12m}{m^{2}-9 } =\frac{12m}{9-m^{2} } \\\\\\2)\\\\\frac{12m}{9-m^{2} } :\frac{12m^{2} }{9-m^{2} }=\frac{12m}{9-m^{2} } \cdot\frac{9-m^{2} }{12m^{2} } =\frac{1}{m} \\\\\\m=0,25\\\\\\\frac{1}{m} =\frac{1}{0,25} =\frac{100}{25} =4\\\\\\Otvet \ : \ 4$