Question

Решите пж ето
4x(3x²-x)
-2a³(a²-2a+4)
(4в²-8в+3)•0,2в

Answer 1

Ответ:

$4x(3 {x}^{2} - x) = 12 {x}^{3} - 4 {x}^{2}$

$- 2 {a}^{3} ( {a}^{2} - 2a + 4) = - 2 {a}^{5} + {4a}^{4} - 8 {a}^{3}$

$(4 {b}^{2} - 8b + 3) \times 0.2b = 0.8 {b}^{3} - 1.6 {b}^{4} + 0.6b$