Question

Solve the the x: 3+log3(5x)=6

Answer 1

$\displaystyle\bf\\ODZ \ : x > 0\\\\3+\log_{3} (5x)=6\\\\\log_{3} (5x)=6-3\\\\\log_{3} (5x)=3\\\\5x=3^{3} \\\\5x=27\\\\\boxed{x=5,4}$

Answer 2

Ответ:

everywhere X>0. This is a simple logarithm equation. Tell me what kind of program or test you are taking