Question

Завдання на фото даю 40 балів​

Answer 1

$\displaystyle\bf\\\left \{ {{(x+1)(x-8)-5x\geq (x-9)(x+9)+1} \atop {\dfrac{24x-15}{9} > 2x-1}} \right. \\\\\\\left \{ {{x^{2} -8x+x-8-5x\geq x^{2} -81+1} \atop {\dfrac{24x-15}{9} \cdot 9 > (2x-1)\cdot 9}} \right.\\\\\\\left \{ {{x^{2} -7x-5x-x^{2} \geq -80+8} \atop {24x-15 > 18x-9}} \right. \\\\\\\left \{ {{-12x\geq -72} \atop {24x-18x > -9+15}} \right. \\\\\\\left \{ {{x\leq 6} \atop {6x > 6}} \right. \\\\\\\left \{ {{x\leq 6} \atop {x > 1}} \right. \\\\\\Otvet \ : \ x\in\Big(1 \ ; \ 6\Big]$