Question

Помогите пожалуйста! Фото заданий ниже

Answer 1

Ответ:

1) $\frac{4}{9} *\frac{3}{32} =\frac{1}{3} *\frac{1}{8} =\frac{1*1}{3*8} =\frac{1}{24}$

2) $5*2\frac{1}{5} =5*\frac{11}{5} =11$

3) $\frac{5}{9} *\frac{3}{20} =\frac{1}{3} *\frac{1}{4} =\frac{1*1}{3*4} =\frac{1}{12}$

4) $\frac{3}{8} *24=3*3=9$

5) $6\frac{6}{7} *\frac{3}{8} =\frac{48}{7} *\frac{3}{8} =\frac{6}{7} *3=\frac{6*3}{7} =\frac{18}{7}$

6) $\frac{5}{12} *\frac{24}{25} *\frac{5}{18} =\frac{2}{5} *\frac{5}{18} =\frac{1}{9}$

7) $1,4*1\frac{1}{14} =1\frac{4}{10} *\frac{15}{14} =\frac{14}{10} *\frac{15}{14} =\frac{1}{2} *\frac{3}{1} =\frac{1*3}{2*1} =\frac{3}{2}$

8) $64*(\frac{3}{4} )^{2} *1\frac{2}{9} =64*\frac{3^{2}}{4^{2}} *\frac{11}{9} =64*\frac{9}{16} *\frac{11}{9} =4*9*\frac{11}{9}=4*11=44$

1) $(\frac{4}{6} +\frac{5}{18} )*36=(\frac{12}{18} +\frac{5}{18} )*36=\frac{12+5}{18} *36=\frac{17}{18} *36=17*2=34$

2) $1\frac{5}{7} *2\frac{1}{10} +2\frac{1}{10} *1\frac{1}{7} =(\frac{12}{7} +\frac{8}{7} )*2\frac{1}{10} =(\frac{12+8}{7} )*\frac{21}{10} =\frac{20}{7} *\frac{21}{10} =$

$=\frac{2}{1} *\frac{3}{1} =2*3=6$

1) $\frac{5}{24} x+\frac{7}{12} x-\frac{11}{36} x=(\frac{5}{24} +\frac{7}{12} -\frac{11}{36} )x=(\frac{15}{72} +\frac{42}{72} -\frac{22}{72} )x=$

$=(\frac{15+42-22}{72} )x=(\frac{57-22}{72} )x=\frac{35}{72} x$

2) $\frac{9}{10} x*3\frac{1}{3} y=\frac{9}{10} x*\frac{10}{3} y=\frac{9}{10} *\frac{10}{3} xy=3xy$