Question

Найдите третий член в биномиальном разложении (х-2)^6 ​

Answer 1

Ответ:

Пошаговое объяснение:x-2/6+x/2 = 5x-2/9

5x-x-x/2 = 2/9-2/6

7/2x = -1/9

x = -1/9*2/7

x = -2/63

5+2x/3=x-3/5+x+5/2

2x-2/3x = 5+3/5-5/2

4/3x = 31/10

x = 31/10*3/4

x = 93/10

3(x+1)/8+2(5x)/3=16-13x/12     ×24

9(x+1)+16*5x = 384-26x

9x+9+80x = 384-26x

89x+26x = 384-9

115x = 375

x = 375/115 = 75/23 = 3 6/23

5(7-2x)/3-4x-2/9=x-19/2    ×18

30(7-2x)-72x-4 = 18x-171

210-60x-72x-4 = 18x-171

18x+60x+72x = 210-4+171

150x = 377

x = 377/150 = 2 77/150