Предмет: Химия, автор: ДианаНикитос

Навеску натрия массой 2,3 г опустили в химический стакан с водой.Вычислите массу и объем (н.у) выделившегося водорода, массу образовавшейся щелочи.

Ответы

Автор ответа: Galush

2Na+2H2O=2NaOH=H2

2,3г:23г/моль=0.1 моль натрия

Пропорция:

0,1/2=Х/22,4л

Объем водорода-1,12л

0,1/2=У/80г

Масса щелочи-4г

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