Question

Решите неравество   1) 2(3х+1)-х<3(х+4)     2)7х+4(х-2)>6(1+3х)    
 3) 2(х-1)-3(х+2)<6(1+х)        4) 7(у+3)-2(у+2)>2(5у+1)                                                             5) 6(3+5у)-(2+7у)<5(4+3у)       6) 4(3у-1)-3(у-1)>2(3+у)          

Answer 1

2(3х+1)-х<3(х+4)
6x+2-x<3x+12
6x-x-3x<12-2
2x<10
x<5


7х+4(х-2)>6(1+3х)
7x+4x-8>6+18x
7x+4x-18x>6+8
-7x>14
x<-2


2(х-1)-3(х+2)<6(1+x)
2x-2-3x-6<6+6x
2x-3x-6x<6+2+6
-7x<14
x>-2


7(у+3)-2(у+2)>2(5у+1)
7y+21-2y-4>10y+2
7y-2y-10y>2-21+4
-5y>-15
y<3


6(3+5у)-(2+7у)<5(4+3у)
18+30y-2-7y<20+15y
30y-7y-15y<20-18+2
8y<4
y<0,5


4(3у-1)-3(у-1)>2(3+у)
12y-4-3y+3>6+2y
12y-3y-2y>6+4-3
7y>7
y>1